Correct answer: Qc71...Rf3/Rf4/R:e2[a]/Rg2/Rh2 2.Qc4#[A]/Qd5#[Б] 1...Ng2/Ng4/[б]//Nd1/Nc2/Nc4[c] 2.N:f5#[C] 1...a6/a5 2.Q:b6# 1...b5 2.Qc5#
