Correct answer: Qf41...Ng4[a]/Nd1/[б]//Nd5/Nc4 2.Qd1# 1.Qa2? (2.Q:f2#) 1...Ng4[a] 2.Q:b1#[A] 1...Nd1/[б]//Nc2 2.Qg8#[Б] 1...Bg3[c]/B
