Correct answer: Nd41...Bf4/Nf4[a] 2.Bd4#[A] 1...Nf6/[б]/ 2.Qd6#[Б] 1.Nd6? (2.R:d5#) 1...Nf4[a] 2.Nf3#[C] 1...Nf6/[б]/ 2.Nf7#[D] but 1...b5! 1.<
