Correct answer: Qc61.Qe1? (2.Qe8#) 1...R:a8[a] 2.Qa5#[A] 1...R:d7/[б]/ 2.Rf8#[Б] 1...Ng7/Ne7[c] 2.Qe7#[C] 1...Ne3 2.Qh4# but 1...Be3! 1.