Correct answer: c31...Q:d3 2.Q:d3# 1.Qb2[A]? (2.c4#[Б]) 1...Q:d3 2.c:d3# but 1...Qb6[a]! 1.Ra2[C]? (2.c3#[D]) 1...Qg8[c]/Qe6[c]/Qf7[c] 2.c4#[Б] but 1...Qa6/