Correct answer: Ba61...Ke4[a]/Ng4/Ng8/Nh5/Nh7/Ne8/Nd7 2.Nfe5#[A] 1...K:c6/[б]/ 2.Nd4#[Б] 1.Be6+? 1...Ke4[a] 2.Nfe5#[A] 1...K:e6/K