Correct answer: Rh51...b5[a] 2.Bb4#[A] 1.Rc7? zz 1...b5[a] 2.Bb4#[A] 1...Kb5/[б]/ 2.Rc5#[Б] but 1...b6! 1.Nb4[C]? zz 1...b5[a] 2.Nc6#[E] 1...Kb5/[б]/ 2.Rh5
