Correct answer: Q:f71...f:e6[a]/Q:e6/[б]/ 2.Be4#[A] 1...Q:d7/Qc7/Qb8 2.Rb5# 1.Bf6[Б]? (2.R:d6#[C]) 1...f:e6[a]/Q:e6/[б]/ 2.Be4#[A] 1...Q:c6[c]/Qe7[d]
