Correct answer: N:c61...Kc4[a]/Nd1 2.Ba6#[A] 1...Nb6/Nc5 2.Rb:c3# 1.B:c6? zz 1...Kc4[a] 2.Bb5#[Б] 1...Q:b3/[б]//Nc4[c] 2.Be4#[C] 1...Nb6/
