Correct answer: Qa81...Kb3 2.Rd3# 1.e6[A]? zz 1...Bc5[a] 2.d:c5#[Б] 1...Ba3[c]/Ba5[d] 2.d5#[C] 1...Kb3 2.Rd3# but 1...B:d6/[б]/! 1.d5[C]? zz 1...B:d6/[б]/