Correct answer: Ng31...Nd3[a]/Nd7[a]/Ne4/[б]//Nb7[a]/Na4[a]/Na6[a] 2.Bd4#[A] 1...Ne3[c]/Ne7[c]/Nf4[d]/Nf6[c]/Nc3[c]/Nc7[c]/Nb4[c]/Nb6[c] 2.Q