Correct answer: Qce3+1...Ka8[a] 2.Qca3#/Qa5# 1...Qd7/Qe7/Qg7/Qh7/Q7a8 2.Qa5# 1.Qcd4+? 1...Ka8[a] 2.Qa4#[A] 1...Qb6/[б]/ 2.Qa3#[Б] but
