Correct answer: Kf41...Bf3[a]/Bd3+[a] 2.Rd3#[A] 1...B:g4+/[б]/ 2.Q:g4#[Б] 1...B:e3[c]/Bb2 2.Bb2#[D] 1...d:e5[d]/d5 2.Bc5#[E] 1...Ne6/Nf7/Nc6/Nb7 2.N