Correct answer: Qb51...Nd3 2.Qc6# 1...Nd5 2.Qc2# 1.Qc5? (2.Qf5#[A]) 1...Nd5 2.Qc2# but 1...Kd3! 1.Qf7? (2.Qf5#[A]/Qf3#[Б]) 1...e1N 2.
