Correct answer: Qh11...K:e2[a] 2.Qg2#[A] 1.Qa3? (2.Q:b2#) 1...K:e2[a] 2.Qe3#[C] 1...Kc2/[б]/ 2.Qc3#[Б] 1...Nc4[c]/Nd3[d]/Na4[c] 2.Qd3#[D] but 1.
