Correct answer: Nb31...Nh1/Nh5/Nf1/Ne2/Ne4[a] 2.Be4#[A] 1...e:d4/[б]/ 2.Ra5#[Б] 1...N:d4[c] 2.Bc4#[C] 1.Bb2? (2.Bc4#[C]/Ra5#[Б]) 1...Ne4[a] 2.