Correct answer: Ba51...Ke5[a] 2.R:d5#[A]/Q:e3#[Б] 1...K:c5/[б]/ 2.Q:c3#[C] 1...Kd3 2.Qd1# 1.Ng2? (2.Q:e3#[Б]) 1...Ke5[a] 2.R:d5#[A] 1...K:c5/[б]/ 2
