Correct answer: Bd41...Qd4 2.Q:d4# 1...Qd6 2.Q:d6#/Qb5#[A] 1.Qh7? (2.Qh3#) 1...Q:e4[a] 2.Q:e4#[D] 1...Q:b3/[б]/ 2.Qd7#[Б] 1...Q:e5[c] 2.R
