Correct answer: Nc31...Bd4[a]/Ne3[a]/Nf4[a]/Nf6[a]/Nc3[c]/Nb6[d] 2.a:b4#[Б] 1...Bc3/[б]/ 2.R:d5#[A] 1...Bf4/Bg3/Bh2/Bf6/Bg7/Bh8/Bb2/Ba
