Correct answer: Qb61...Kd5[a] 2.Bg2#[A] 1.Qc8? (2.Qf5#) 1...Kd5[a] 2.Qe6#[D] 1...Kd3/[б]/ 2.Qc2#[C] 1...Kf3 2.Qg4# but 1...Kf4! 1.Qc7? zz