Correct answer: Nc31...Bc2[a] 2.N:c2#[A] 1...B:d3/[б]/ 2.N:d3#[Б] 1...Re4[c]/Re3[d]/Re2[d]/R:e1[d]/Re6/Re7/Re8/Rd5/R:c5[e] 2.Bc3#[C] 1.c6? zz
