Correct answer: Qe51...K:d8[a] 2.Qd7#[A] 1...K:f8/[б]/ 2.Qf7#[Б] 1.Kb2?? zz 1...K:d8[a] 2.Qd7#[A] 1...K:f8/[б]/ 2.Qf7#[Б] but 1...b3! 1.Kc2?? zz 1...