Correct answer: Bf61...Ne1[a]/Ne5/[б]//Nf2[c]/Nc1[a]/Nc5[a]/Nb2[a]/Nb4[a] 2.R:f4#[A] 1...Ng2[d]/Ng6[e]/Nh3[d]/Ne2[f]/Ne6[g] 2.Qf6#[Б] 1.Kh