Correct answer: Qb41...Ne4[a] 2.Qf7#[A] 1...Nc4/[б]/ 2.Qb7#[Б] 1.Qf4? (2.Qb7#[Б]) 1...Ne4[a] 2.Qf7#[A] 1...Nc4/[б]/ 2.e4#[D] 1...Nf1[d]/Nf3[c]/N