Correct answer: Bd31...Kc5/Kc6[a]/d3 2.Ne3#[A] 1.Kf6? zz 1...Kc5/Kc6[a]/d3 2.Ne3#[A] 1...c6[c] 2.Nb6#[Б] but 1...c5/[б]/! 1.Qc2? zz 1...Kc5/Kc6[a]
