Correct answer: Bh51...g6[a] 2.Be6#[A] 1...g5/[б]/ 2.f:e5#[Б] 1.Bd2? zz 1...g6[a] 2.Be6#[A] 1...g5/[б]/ 2.f:g5#[E] 1...e:f4[c] 2.Q:f4#[C] 1...e4[d] 2.Qh3#[D] but 1...h5! 1.Bd
