Correct answer: Na41...Qe3+[a] 2.B:e3#[A] 1...Qg5+/[б]/ 2.B:g5#[Б] 1...Qf4 2.B:f4# 1.N:c4?? (2.Qc2#) 1...Qe3+[a] 2.Kg2#[C] 1...Qg5+/[б]/ 2.Kf2#[D]