Correct answer: Bg51...Rf1[a] 2.c3#[A] 1...Q:d6/Nc4/[б]/ 2.Qd3#[C] 1...a6 2.B:b6# 1...Re2/Rd2/Rg2/Rh2 2.N:f3#[Б] 1...R:c2+ 2.N:c2# 1...Ng3/Ng7