Correct answer: Ra51...e6/e5[a] 2.Q:d7#[A] 1...d6/[б]//d5 2.Q:e7#[Б] 1.Qb8? (2.Qh2#) 1...e5[a] 2.R:d7#[C] 1...d6/[б]/ 2.R:e7#[D] but 1...Bg2! 1.Qc7? (2.Qh2#)
