Correct answer: Ne21...d1Q[a]/d1R[a] 2.Rc4#[A] 1...d1N/[б]/ 2.Bd3#[Б] 1...d1B 2.Rc4#[A]/Bd3#[Б] 1.Nd3? zz 1...d1Q[a]/d1R[a] 2.Qb2#[C] 1...d1N