Correct answer: Nd31...c4[a] 2.Qe5#[C] 1...f2/[б]/ 2.Nd2#[Б] 1...Bh4[c] 2.Qd5#[D] 1...Ne3 2.Ng3#[A]/Nd2#[Б] 1.Rb3? (2.Ng3#[A]/Nd2#[Б]) 1...Bh4[c] 2.Nd
