Correct answer: Qf31...Bd3[a]/Be2[a]/Bf1[a]/Bd5[a]/Be6/[б]//Bf7[a]/Bg8[a]/Bb3[a]/Ba2[a]/Bb5[a]/B:a6[a] 2.Bd8#[A] 1...c5[c] 2.Bd2#[Б] 1.Bc3? zz
