Correct answer: Nf51...Nd7/Nb7/Na4/Na6 2.Rf4#/Qd4#[A] 1.Qd6? (2.Qd4#[A]) 1...Ne6[a]/Rd8 2.Q:e5#[C] 1...Rd5/[б]/ 2.Qf4#[D] 1...K:e3 2