Correct answer: Qa31...Kf6[a] 2.Qh8#[A] 1...K:d6/[б]/ 2.Qb8#[Б] 1.Qa5? (2.Ne4#) 1...Kf6[a]/e:d6[c] 2.Qc3#[C] 1...K:d6/[б]/ 2.N:b7#[D] but 1...Nd3! 1.
