Correct answer: Qd11...Bd5[a] 2.Qc3#[A] 1...R:b3/[б]/ 2.Qe4#[C] 1...Nh4/Nh8/Nf4/Nf8/Ne7 2.Rf4# 1...Nf7 2.Qd3#/Qc3#[A]/Qd5#[Б] 1...Ng4/