Correct answer: Nd31...K:e6[a] 2.Qf7#[A] 1...R:e6/[б]//d:e6 2.Qg2#[Б] 1.N:d7? (2.Qe5#) 1...K:e6[a] 2.Qg8#[D] 1...R:e6/[б]/ 2.Rc5#[C] but 1...B:f4! 1.