Correct answer: Qb11...Ne6[a]/Nb3/[б]//Nb7/[б]//Na4/[б]//Na6[c] 2.B:d3#[A] 1...Ne1[d]/Nf2[d]/Nc1[d]/Nb2[d] 2.R:c5#[Б] 1...N:d7 2.B:d3#[A]/B:d7# 1.