Correct answer: Qe61...Kf5[a] 2.Bd3#[A] 1...Kd5/[б]/ 2.Bb7#[Б] 1.Qb4+? 1...Kf5[a] 2.Q:g4#[C] 1...Kd5/[б]/ 2.Qc4#[D] 1...Ke3 2.Qf4#/N:g4# but 1