Correct answer: Nd31...Qb7/Qb8/Qd3[a]/Qe2/Qf1/Qd7/[б]//Qe8/Qa4/Qa6 2.N:c5#[A] 1...c4 2.Nd4# 1.Nd7? (2.f5#) 1...Qd3[a] 2.Nd:c5#[Б] 1...<
