Correct answer: Bh41...Kd5[a] 2.Qe5#[A] 1...Kf5 2.Qg4# 1.Qh4? zz 1...Kd5[a] 2.Qc4#[C] 1...K:f7/[б]/ 2.Qf6#[Б] 1...Kf5 2.Qg4# but 1...Kd7!
