Correct answer: Re21...Ng2[a]/Nc2 2.Q:g2#[A] 1...Nd3/[б]/ 2.Qg2#[A]/Q:d3#[Б] 1...N:h3[c] 2.Q:h3#[C]/Qe2#[D] 1...Ne2 2.Q:e2#[D] 1.Rg2[E]? (2.Q:f2#)
