Correct answer: Bb51...Kd5[a] 2.Qd3#[A] 1...Ke4/[б]/ 2.Qc4#[Б] 1.Be6? (2.Qc4#[Б]) but 1...f:e6! 1.Bf5? (2.Qd3#[A]) but 1...Kd5[a]! 1.Bd6[C]? zz 1...K