Correct answer: Rb71.Rf3? (2.Qb3#) 1...Kd5[a] 2.Ne3#[A] 1...Rc6/[б]//Rc7/Rc8/Rb5/Ra5[c]/Re5[c]/Rf5[c]/Rg5[c]/Rh5[c] 2.R:c6#[Б] 1...R