Correct answer: Be21.Rd4[A]? (2.Ra4#) 1...Rg4[c] 2.Be2#[Б] but 1...Rg5[a]! 1.Rd5[C]? (2.Ra5#) 1...Rg5[a] 2.Be2#[Б] but 1...Rg6/[б]/! 1.Rd6[D]? (2.