Correct answer: Qh61...Ke2/Ke4[a] 2.Q:c2#[A] 1...d4/[б]/ 2.Qc4#[Б] 1.Qc5?? (2.Qe3#) 1...Ke2/Ke4[a] 2.Q:c2#[A] 1...d4/[б]/ 2.Qc4#[Б] but 1...N:c5! 1.<
