Correct answer: Bc41...Nc3[a]/Nd2/Na3/[б]/ 2.Q:c3#[A] 1...a3[c] 2.Qc4#[Б] 1...Qa5[d] 2.Bc5#[C] 1...R:c6 2.N:c6# 1...R:b8/Rd8/Re8/Rf8/Rg8/R