Correct answer: Rd41.Bc6[A]? (2.Ra6#[Б]/c:b4#[C]) 1...B:c3[a] 2.Rd5#[D] 1...Bd6/Be7/Bf8/Ba3 2.Ra6#[Б] 1...Bd3 2.c:b4#[C] but 1...Bc5! 1.Rd5[D]?
