Correct answer: Nc41...Be5[a] 2.Rd3#[A] 1...N:e3/[б]/ 2.Qa1#[C] 1...Ne1/Nb4[c]/Na1 2.Rb4#[Б] 1...Nh1/Nh5/Nf1/N:e2/Ne4[d] 2.N:f5#[D] 1...a5 2.