Correct answer: Rb51.Rb6?? (2.Qa2#/Be6#) 1...Qf7/Qe8/Qc8/Qg8/Qd6 2.Rd6#/Qa2# 1...Q:f6/Qe7 2.Qa2# 1...Qa8 2.Be6#/Rd6# 1
