Correct answer: Qg11.Qc1? zz 1...Kf6[a] 2.Ng4#[A] 1...Kd4/[б]/ 2.Qc3#[Б] 1...Kd6[c] 2.Qc7#[C] but 1...Kf4! 1.Qg1! zz 1...Kf6[a] 2.Qg7#[D]
